The difference between a two-digit number and the number obtained by interchanging the positions of its digits is 36. What is the difference between the two-digits of that number?
Created: 5 years ago |
Updated: 6 months ago
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Let the two-digit number be 10x+y, where x is the digit in the tens place and y is the digit in the units place.
When the digits are interchanged, the number becomes 10y+x.
According to the given information, the difference between the two-digit number and the number obtained by interchanging the positions of its digits is 36. Mathematically, this can be represented as:
(10x+y)−(10y+x)=36
Simplifying the equation:
10x+y−10y−x=36 9x−9y=36 x−y=4
So, the difference between the two digits of the number is 4.
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